An aromatic compound "A" on treatment with Zn | vedclass

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Question

(B) The reaction of an aromatic nitro compound $(Ar-NO_2)$ with $Zn / NH_4Cl$ is a selective reduction that produces an aromatic hydroxylamine $(Ar-NH

Vedclass · Accepted Answer

$-NO_2$

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(B) The reaction of an aromatic nitro compound $(Ar-NO_2)$ with $Zn / NH_4Cl$ is a selective reduction that produces an aromatic hydroxylamine $(Ar-NHOH)$.$Ar-NO_2 + Zn / NH_4Cl \rightarrow Ar-NHOH + ZnO$Aromatic hydroxylamines are strong reducing agents and can reduce Tollen's reagent (ammoniacal silver nitrate) to metallic silver $(Ag)$,which appears as a black precipitate.$Ar-NHOH + 2[Ag(NH_3)_2]^+ + 3OH^- \rightarrow Ar-NO + 2Ag(s) + 4NH_3 + 2H_2O$Therefore,the functional group present in compound "$A$" is the nitro group $(-NO_2)$.

An aromatic compound "$A$" on treatment with $Zn / NH_4Cl$ and subsequent heating with ammoniacal silver nitrate solution gives a black precipitate. Which functional group does "$A$" contain?

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